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Text Solution:

We have an inverse variation relationship between the weight (w) of each child and his distance (d) from the fulcrum. Thus, our initial equation is $d=\frac{k}{w}$. We use the information about Saroya to determine the value of k by substituting 62 for w and 6 for d.

$\begin{array}{l}\Rightarrow d=\frac{k}{w}\\ \Rightarrow 6=\frac{k}{62}\\ \Rightarrow 372=k\end{array}$

Now that we know that k is 372, our inverse variation equation is $d=\frac{372}{w}$. Let’s now find how far Nitish, who weighs 80 pounds, must sit from the fulcrum so that the seesaw will be balanced.

$\begin{array}{l}\Rightarrow d=\frac{372}{w}\\ \Rightarrow d=\frac{372}{80}\\ \Rightarrow d=4.65\end{array}$

Nitish should sit 4.65 feet from the fulcrum to balance the seesaw.